Mohanraj
AIM
To write a program to implement the
FCFS scheduling algorithm
ALGORITHM
1. Start the process
2. Declare the array size
3. Get the number of processes to be inserted
4. Get the value
5. Start with the first process from it’s initial position
let other process to be in queue
6. Calculate the total number of burst time
7. Display the values
8. Stop the process
PROGRAM:
#include<stdio.h>
main()
{
int
n,a[10],b[10],t[10],w[10],g[10],i,m;
float att=0,awt=0;
for(i=0;i<10;i++)
{
a[i]=0; b[i]=0; w[i]=0; g[i]=0;
}
printf("enter
the number of process");
scanf("%d",&n);
printf("enter
the burst times");
for(i=0;i<n;i++)
scanf("%d",&b[i]);
printf("\nenter the arrival
times");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
g[0]=0;
for(i=0;i<10;i++)
g[i+1]=g[i]+b[i];
for(i=0;i<n;i++)
{
w[i]=g[i]-a[i];
t[i]=g[i+1]-a[i];
awt=awt+w[i];
att=att+t[i];
}
awt =awt/n;
att=att/n;
printf("\n\tprocess\twaiting
time\tturn arround time\n");
for(i=0;i<n;i++)
{
printf("\tp%d\t\t%d\t\t%d\n",i,w[i],t[i]);
}
printf("the
average waiting time is %f\n",awt);
printf("the
average turn around time is %f\n",att);
}
OUTPUT:
enter the number of process 4
enter the burst times
4
9 8 3
enter the arrival times
0
2 4 3
process waiting time turn arround time
p0 0 4
p1 2 11
p2 9
17
p3 18
21
the average waiting time is
7.250000
the average turn around time is
13.250000
Posted in: C / C++ Program
8 comments:
hi frnds ple corect the folowing program
#include
{
int p1,p2,p3,p4;
int p[1]=2.p[2]=10,p[3]=14,p[4]=16;
printf("the cpu burset time is =",p[1],p[2],p[3],p[4]);
scanf("%d",&p[1]&,p[2]&,p[3]&,p[4]);
for(i=1;i<=4;i++)
{
int x[0],p[0]=0;
waiting timex[i]=x[i-1]+p[i-1];
}
printf("waiting time of cpu is=",&x1);
printf("waiting time of cpu is=",&x2);
printf("waiting time of cpu is=",&x3);
printf("waiting time of cpu is=",&x4);
average time is a=x[4]/4;
printf("average time is=",&a);
}
scanf("%d%d%d%d",&p[1]&,p[2]&,p[3]&,p[4]);
scanf(%d)
Mohsin
#include is missing according to my point of view.ok
what is g[10] in this code plz reply soon
where is main() function??
What is the purpose of using printf statement at line 5??
working but not displaying turn around time of process....
working but see this also after some editing in this program
#include
#include
#include
void main()
{
clrscr();
int n,a[10],b[10],t[10],w[10],g[10],i,m;
float att=0,awt=0;
for(i=0;i<10;i++)
{
a[i]=0; b[i]=0; w[i]=0; g[i]=0;
}
printf("enter the number of process:\n");
scanf("%d",&n);
printf("enter the arrival times:\n");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("enter the burst times:\n");
for(i=0;i<n;i++)
scanf("%d",&b[i]);
g[0]=0;
for(i=0;i<10;i++)
g[i+1]=g[i]+b[i];
for(i=0;i<n;i++)
{
w[i]=g[i]-a[i];
t[i]=g[i+1]-a[i];
awt=awt+w[i];
att=att+t[i];
}
awt =awt/n;
att=att/n;
printf("\n\tprocess\t A_time\t B_time\t W_time\t TA_time\n");
for(i=0;i<n;i++)
{
printf("\tp%d\t%d\t%d\t%d\t%d\n",i,a[i],b[i],w[i],t[i]);
}
printf("the average waiting time is :%f\n",awt);
printf("the average turn around time is :%f\n",att);
getch();
}
output:
enter the arrival times:
0 1 2
enter the burst times:
2 2 20
process A_time B_time W_time TA_time
p0 0 2 0 2
p1 1 2 1 3
p2 2 20 2 22
the average waiting time is : 1.000000
the average turn around time is : 9.000000
and the output is correct i have solved it
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